How do you solve #4a - 3( a - 2) = 2( 3a - 2)#?

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Answer 1 · 2016-10-28T22:28:34

#a = 2#

To solve this first expand the equation to eliminate the parenthesis:

#4a - 3a + 6 = 6a - 4#

Consolidating like terms gives:

#a + 6 = 6a - 4#

Do the following to solve for #a#

#a - a + 6 + 4 = 6a - a - 4 + 4#

#10 = 5a#

#10/5 = (5a)/5#

#a = 2#