First, subtract #color(red)(4a)# and #color(blue)(15)# from each side of the inequality to isolate the #a# term while keeping the inequality balanced:
#-color(red)(4a) + 4a + 5 - color(blue)(15) > -color(red)(4a) + 9a + 15 - color(blue)(15)#
#0 - 10 > (-color(red)(4) + 9)a + 0#
#-10 > 5a#
Now, divide each side of the inequality by #color(red)(5)# to solve for #a# while keeping the inequality balanced:
#-10/color(red)(5) > (5a)/color(red)(5)#
#-2 > (color(red)(cancel(color(black)(5)))a)/cancel(color(red)(5))#
#-2 > a#
To state the solution in terms of #a# we can reverse or "flip" the entire inequality:
#a < -2#
