How do you solve #4b - 2( 2b + 5) = 4b + 2#?

1 Answer
smendyka
May 9, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#4b - color(red)(2)(2b + 5) = 4b + 2#

#4b - (color(red)(2) * 2b) - (color(red)(2) * 5) = 4b + 2#

#4b - 4b - 10 = 4b + 2#

#0 - 10 = 4b + 2#

#-10 = 4b + 2#

Next, subtract #color(red)(2)# from each side of the equation to isolate the #b# term while keeping the equation balanced:

#-10 - color(red)(2) = 4b + 2 - color(red)(2)#

#-12 = 4b + 0#

#-12 = 4b#

Now, divide each side of the equation by #color(red)(4)# to solve for #b# while keeping the equation balanced:

#-12/color(red)(4) = (4b)/color(red)(4)#

#-3 = (color(red)(cancel(color(black)(4)))b)/cancel(color(red)(4))#

#-3 = b#

#b = -3#

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