How do you solve #4k ^ { 2} - 6= 250#?

1 Answer
Nov 20, 2017

#k=+-8#

Explanation:

#"add 6 to both sides"#

#4k^2cancel(-6)cancel(+6)=250+6#

#rArr4k^2=256#

#"divide both sides by 4"#

#(cancel(4) k^2)/cancel(4)=256/4#

#rArrk^2=64#

#color(blue)"take the square root of both sides"#

#sqrt(k^2)=+-sqrt64larrcolor(blue)"note plus or minus"#

#rArrk=+-8#