How do you solve #4k ^ { 2} - 6= 250#?
1 Answer
Nov 20, 2017
Explanation:
#"add 6 to both sides"#
#4k^2cancel(-6)cancel(+6)=250+6#
#rArr4k^2=256#
#"divide both sides by 4"#
#(cancel(4) k^2)/cancel(4)=256/4#
#rArrk^2=64#
#color(blue)"take the square root of both sides"#
#sqrt(k^2)=+-sqrt64larrcolor(blue)"note plus or minus"#
#rArrk=+-8#