How do you solve #4n + 2+ 4= 5n + 8#?

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Answer 1 · 2017-11-22T23:15:55

See a solution process below:

First, combine like terms on the left side of the equation:

#4n + (2 + 4) = 5n + 8#

#4n + 6 = 5n + 8#

Now, subtract #color(red)(4n)# and #color(blue)(8)# from each side of the equation to solve for #n# while keeping the equation balanced:

#4n - color(red)(4n) + 6 - color(blue)(8) = 5n - color(red)(4n) + 8 - color(blue)(8)#

#0 - 2 = (5 - color(red)(4))n + 0#

#-2 = 1n#

#-2 = n#

#n = -2#