# How do you solve 4n^2 - 9n + 5 = 0?

Jan 8, 2016

x=1 or 1.25

#### Explanation:

As we clearly see that factorisation is difficult so I suggest we use the quadratic formula for this.

The quadratic formula states that for an equation of the form $a {x}^{2} + b x + c = 0$, the value of x can be calculated as

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

Comparing this with your question
x=n
a=4
b=-9
c=5

Plug in these values and find the values of n.