How do you solve #4n + 3= - 1#?

1 Answer
Feb 18, 2017

#n=-1#

Explanation:

Given
#color(white)("XXX")4n+3=-1#

If we subtract the same amount form both sides of an equality, the equality is maintained.
In this case we will subtract #3# from both sides so that we have the variable term on one side and only a constant on the other:
#color(white)("XXX")4n+3color(red)(-3)=-1color(red)(-3)#

#color(white)("XXX")rarr 4n=-4#

If we divide both sides of an equality by the same (non-zero) amount, the equality is also maintained.
In this case we will divide both sides by #4#
#color(white)("XXX")(4n)/color(red)4=(-4)/color(red)(4)#

#color(white)("XXX")rarr n=-1#