Question

How do you solve `4t-13=57`?

Answer 1

The solution is `t=17.5`.

Explanation:

To solve the problem, we want to end up with `t` by itself on one side. To do that, we need to perform actions on both sides of the equals sign that are the same.

In this case, we should add `13` first:

`4t-13=57`

`4t-13color(blue)+color(blue)13=57color(blue)+color(blue)13`

`4tcolor(red)cancelcolor(black)(color(black)-13color(blue)+color(blue)13)=57color(blue)+color(blue)13`

`4t=57color(blue)+color(blue)13`

`4t=70`

Now, we can divide both sides by `4` to get `t` by itself:

`color(blue)(color(black)(4t)/4)=color(blue)(color(black)70/4)`

`color(blue)(color(black)(color(red)cancelcolor(black)4t)/color(red)cancelcolor(blue)4)=color(blue)(color(black)70/4)`

`t=color(blue)(color(black)70/4)`

`t=17.5`

That's the solution to the problem. Hope this helped!

Answer 2

`t=17.5`

Explanation:

First, in order to get t by itself you have to add `13` to both sides, so it will cancel out on the side it was previously on, after you do so your new equation will be `4t=70`. Then again, to get `t` by itself you will divide `70` by `4` so you can remove it from the other side, this will leave you equation as `t=17.5`.

Answer 3

`t = 17 1/2`

Explanation:

You need to isolate the term with the variable,

Add `13` to both sides first.

`4t -13 color(blue)(+13) = 57`

`4tcolor(white)(xx.xxxx) =70 color(blue)(+13)" "larr (-13+13=0)`

You now need to isolate `t`.
Divide both sides by `4`

`(cancel4t)/cancelcolor(red)(4)color(white)(xx.xxxx) =70/color(red)(4)`

`" "tcolor(white)(xx.xxxx) =35/2 = 17 1/2`