How do you solve #4t - 3> 37t- 50#?

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Answer 1 · 2018-04-06T13:38:31

See a solution process below:

First, subtract #color(red)(4t)# and add #color(blue)(50)# to each side of the the inequality while keeping the inequality balanced:

#4t - color(red)(4t) - 3 + color(blue)(50) > 37t - color(red)(4t) - 50 + color(blue)(50)#

#0 + 47 > (37 - color(red)(4))t - 0#

#47 > 33t#

Now, divide each side of the inequality by #color(red)(33)# to solve for #t# while keeping the inequality balanced:

#(47)/color(red)(33) > (33t)/color(red)(33)#

#47/33 > (color(red)(cancel(color(black)(33)))t)/cancel(color(red)(33))#

#47/33 > t#

We can now reverse or "flip" the entire inequality:

#t < 47/33#