How do you solve #4w ^ { 2} - 3w - 10= 0#?

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Answer 1 · 2017-05-12T03:14:36

See a solution process below: #w = -5/4# and #w = 2#

First, factor the quadratic on the left side of the equation as:

#(4w + 5)(w - 2) = 0#

Now, equate each term on the left side of the equation to #0# and solve for #w#:

Solution 1)

#4w + 5 = 0#

#4w + 5 - color(red)(5) = 0 - color(red)(5)#

#4w + 0 = -5#

#4w = -5#

#(4w)/color(red)(4) = -5/color(red)(4)#

#(color(red)(cancel(color(black)(4)))w)/cancel(color(red)(4)) = -5/4#

#w = -5/4#

Solution 2)

#w - 2 = 0#

#w - 2 + color(red)(2) = 0 + color(red)(2)#

#w - 0 = 2#

#w = 2#

The solution is: #w = -5/4# and #w = 2#