How do you solve #4x-10=7-2x#?

3 Answers
Mar 11, 2018

#x=17/6#

Explanation:

Given: #4x-10=7-2x#

Adding #2x# to both sides, we get

#4x-10+2x=7-color(red)cancelcolor(black)(2x)+color(red)cancelcolor(black)(2x)#

#=>6x-10=7#

Adding #10# to both sides, we have

#=>6x-color(red)cancelcolor(black)10+color(red)cancelcolor(black)10=7+10#

#=>6x=17#

Final step is to divide by #6# on both sides.

#=>(color(red)cancelcolor(black)6x)/color(red)cancelcolor(black)6=17/6#

#=>x=17/6#

Mar 11, 2018

#x# = #17/6#

Explanation:

Add 2#x# and 10 to both sides to get 6#x# = 17

Then divide both sides by 6 to leave #x# alone on one side, giving #x# = #17/6#

Mar 11, 2018

#x =17/6#

Explanation:

Move all the #x# terms to one side and the numbers to the other side.

#4x-10=7-2x" "larr# add #2x# to each side

#4x-10color(blue)(+2x) = 7-2xcolor(blue)(+2x)#

#6x -10color(red)(+10) = 7-10color(red)(+10)" "#add#color(red)(10)# to both sides

#6x = 17#

#(6x)/6 =17/6" "larr div 6# on both sides

#x =17/6#