How do you solve #4x - 16+ 6x = 2( 5x - 8)#?

1 Answer
smendyka
Dec 29, 2016

The solution is #x# can be any number.

Explanation:

On the left side of the equation group and combine the like terms.

On the right side of the equation expand the term in parenthesis:

#10x - 16 = 10x - 16#

Isolate the #x# terms on one side of the equation and the constants on the other side of the equation:

#10x - 16 - 10x + 16 = 10x - 16 - 10x + 16#

#0 = 0#

Therefore the solution is #x# can be any number.

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