How do you solve #4x - 1x + 25x + 6= 0#?

Question

514 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-16T03:18:55

See a solution process below:

First, combine like terms on the left side of the equation:

#4color(red)(x) - 1color(red)(x) + 25color(red)(x) + 6 = 0#

#(4 - 1 + 25)color(red)(x) + 6 = 0#

#28x + 6 = 0#

Next, subtract #color(red)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#28x + 6 - color(red)(6) = 0 - color(red)(6)#

#28x + 0 = -6#

#28x = -6#

Now, divide each side of the equation by #color(red)(28)# to solve for #x# while keeping the equation balanced:

#(28x)/color(red)(28) = -6/color(red)(28)#

#(color(red)(cancel(color(black)(28)))x)/cancel(color(red)(28)) = -3/14#

#x = -3/14#