How do you solve 4x^2=0 using the quadratic formula?

Oct 25, 2014

$x = \frac{- b \pm \sqrt[2]{{b}^{2} - 4 a c}}{2 a}$

$4 {x}^{2} = 0$

can be re-written into

$4 {x}^{2} + 0 x + 0 = 0$

Substituting the coefficients into the quadratic formula, we have

$x = \frac{- b \pm \sqrt[2]{{b}^{2} - 4 a c}}{2 a}$

$\implies x = \frac{- 0 \pm \sqrt[2]{{0}^{2} - 4 \left(4\right) \left(0\right)}}{2 \left(4\right)}$

$\implies x = \frac{- 0 \pm \sqrt[2]{0 - 0}}{8}$

$\implies x = 0$