How do you solve #4x - 2 < 10#?

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Answer 1 · 2017-10-06T16:37:24

#x<3#

Pretend that the less than sign is an equals sign,
#4x-2<10->4x-2=10#

Then solve this two step equation:

#4x-2=10#

Add 2 on both sides

#4x=12#

Divide both sides by 4

#x=3#

Replace the equals sign with the less than sign

#x<3#