How do you solve 4x ^ { 2} + 4x - 5= - 6 by extracting square roots?

1 Answer
Oct 9, 2017

x=-1/2

Explanation:

4x^2+4x-5=-6
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rArr4x^2+4x-5+6=0
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rArr4x^2+4x-5+6=0
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rArr4x^2+4x+1=0
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rArr (2x)^2+2 (2x)(1)+(1)^2=0
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rArr (2x+1)^2=0
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"rArr2x+1=0rArr2x=-1rArrx=-1/2
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therefore x=-1/2