How do you solve #4x ^ { 2} + 4x - 5= - 6# by extracting square roots?

1 Answer
Mia
Oct 9, 2017

#x=-1/2#

Explanation:

#4x^2+4x-5=-6#
#" "#
#rArr4x^2+4x-5+6=0#
#" "#
#rArr4x^2+4x-5+6=0#
#" "#
#rArr4x^2+4x+1=0#
#" "#
#rArr (2x)^2+2 (2x)(1)+(1)^2=0#
#" "#
#rArr (2x+1)^2=0#
#" "#
#"rArr2x+1=0rArr2x=-1rArrx=-1/2#
#" "#
#therefore x=-1/2#

Related questions
Impact of this question
1033 views around the world
You can reuse this answer
Creative Commons License