Question

How do you solve `4x^{2} + 7x - 17= 3x^{2} + 12x - 3`?

Answer 1

`x={-2,7}`

Explanation:

`4x^2+7x-17=3x^2+12x-3`

`4x^2+7x-17-3x^2-12x+3=0`

`x^2-5x-14=0`

`(x-7)(x+2)=0`

`x-7=0" "rArr " "x=7`

`x+2=0" "rArr" "x=-2`