How do you solve #4x + 3= 2x - 6#?

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Answer 1 · 2017-06-07T14:19:28

See a solution process below:

First, subtract #color(red)(3)# and #color(blue)(2x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(blue)(2x) + 4x + 3 - color(red)(3) = -color(blue)(2x) + 2x - 6 - color(red)(3)#

#(-color(blue)(2) + 4)x + 0 = 0 - 9#

#2x = -9#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = -9/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -9/2#

#x = -9/2#