How do you solve $4x + 3= 2x - 6$ ?

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Answer 1 · 2017-06-07T14:19:28

See a solution process below:

First, subtract $color(red)(3)$ and $color(blue)(2x)$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$-color(blue)(2x) + 4x + 3 - color(red)(3) = -color(blue)(2x) + 2x - 6 - color(red)(3)$

$(-color(blue)(2) + 4)x + 0 = 0 - 9$

$2x = -9$

Now, divide each side of the equation by $color(red)(2)$ to solve for $x$ while keeping the equation balanced:

$(2x)/color(red)(2) = -9/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -9/2$

$x = -9/2$

How do you solve 4x + 3= 2x - 64x + 3= 2x - 6?