How do you solve #(4x - 35) - ( 3x + 10)#?

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Answer 1 · 2018-01-27T03:24:07

#x = 45#

#(4x-35)-(3x+10) = 0#

Distribute #(-)#:

#4x-35-3x-10 = 0#

Collect Like Terms:

#x-45 = 0#

Isolate for #x#:

#x = 45#