How do you solve #4x=-3x-7#?
1 Answer
Apr 24, 2018
Explanation:
#"add 3x to both sides"#
#4x+3x=cancel(-3x)cancel(+3x)-7#
#rArr7x=-7#
#"divide both sides by 7"#
#(cancel(7) x)/(cancel(7))=(-7)/7#
#rArrx=-1#
#color(blue)"As a check"#
#" left "=(4xx-1)=-4#
#"right "=-(3xx-1)-7=3-7=-4#
#rArrx=-1" is the solution"#
