How do you solve #4x + 4+ 2x = 20#?

1 Answer
Nov 17, 2017

See a solution process below:

Explanation:

First, group and combine like terms on the left side of the equation:

#4x + 2x + 4 = 20#

#(4 + 2)x + 4 = 20#

#6x + 4 = 20#

Next, subtract #color(red)(4)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#6x + 4 - color(red)(4) = 20 - color(red)(4)#

#6x + 0 = 16#

#6x = 16#

Now, divide each side of the equation by #color(red)(6)# to solve for #x# while keeping the equation balanced:

#(6x)/color(red)(6) = 16/color(red)(6)#

#(color(red)(cancel(color(balck)(6)))x)/cancel(color(red)(6)) = (2 xx 8)/color(red)(2 xx 3)#

#x = (color(red)(cancel(color(black)(2))) xx 8)/color(red)(color(black)(cancel(color(red)(2))) xx 3)#

#x = 8/3#