How do you solve $4 x + 5 < 17$ $4x+5<17$ and $4 x - 3 > - 7$ $4x-3 > -7$ ?

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Answer 1 · 2018-05-03T16:52:47

$x < 3$ $x<3$
$x > - 1$ $x> -1$

$4 x + 5 < 17$ $4x+5<17$
=> $4 x < 12$ $4x<12$
=> $x < 3$ $x<3$

$4 x - 3 > - 7$ $4x-3> -7$
$4 x > - 4$ $4x> -4$
$x > - 1$ $x> -1$

How do you solve 4x+5<174x+5<174x+5<17 and 4x-3 > -74x−3>−74x-3 > -7?