How do you solve #4x + 5< 21#?

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Answer 1 · 2018-05-11T02:34:12

#x < 4#

#4x + 5 < 21#

Solving inequalities is similar to solving equations.

First, subtract #color(blue)5# from both sides of the inequality:
#4x + 5 quadcolor(blue)(-quad5) < 21 quadcolor(blue)(-quad5)#

#4x < 16#

Now divide both sides by #color(blue)4#:
#(4x)/color(blue)4 < 16/color(blue)4#

Therefore,
#x < 4#

Hope this helps!