First, on each side of the equation remove all of the terms from their parenthesis, group and combine like terms:
#-4x + 5 = 5x + 7 + 10#
#-4x + 5 = 5x + 17#
Next, add #color(red)(4x)# and subtract #color(blue)(17)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#-4x + color(red)(4x) + 5 - color(blue)(17) = 5x + color(red)(4x) + 17 - color(blue)(17)#
#0 - 12 = (5 + color(red)(4))x + 0#
#-12 = 9x#
Now, divide each side of the equation by #color(red)(9)# to solve for #x# while keeping the equation balanced:
#-12/color(red)(9) = (9x)/color(red)(9)#
#-(3 xx 4)/color(red)(3 xx 3) = (color(red)(cancel(color(black)(9)))x)/cancel(color(red)(9))#
#-(color(red)(cancel(color(black)(3))) xx 4)/color(red)(color(black)(cancel(color(red)(3))) xx 3) = x#
#-4/3 = x#
#x = -4/3#
