How do you solve #4x + 5= \frac { 3} { x }#?
1 Answer
Jul 28, 2017
Explanation:
#"multiply ALL terms by x to eliminate the fraction"#
#rArr4x^2+5x=cancel(x)xx3/cancel(x)#
#rArr4x^2+5x-3=0larrcolor(blue)" in standard form"#
#"with " a=4,b=5,c=-3#
#"solve using the "color(blue)"quadratic formula"#
#x=(-5+-sqrt(25+48))/8#
#rArrx=(-5+sqrt73)/8" or " x=(-5-sqrt73)/8#
#rArrx~~0.443" or "x~~ -1.693#
