How do you solve #4x-7<2x+5#?

1 Answer
Mar 3, 2018

See a solution process below:

Explanation:

First, add #color(red)(7)# and subtract #color(blue)(2x)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#4x - color(blue)(2x) - 7 + color(red)(7) < 2x - color(blue)(2x) + 5 + color(red)(7)#

#(4 - color(blue)(2))x - 0 < 0 + 12#

#2x < 12#

Now, divide each side of the inequality by #color(red)(2)# to solve for #x# while keeping the inequality balanced:

#(2x)/color(red)(2) < 12/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) < 6#

#x < 6#