How do you solve #(4x)/9 - 1/3 = x/3#?

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Answer 1 · 2017-10-03T15:12:12

#x = 3#

#(4x)/9 - 1/3 = x/3#

Multiply through with their LCM, which is #9#

#9(4x)/9 - 9(1/3) = 9(x/3)#

#cancel9(4x)/cancel9 - cancel9^3(1/cancel3_1) = cancel9^3(x/cancel3_1)#

#4x - 3(1) = 3(x)#

#4x - 3 = 3x#

Collect like terms

#4x - 3x = 3#

#x = 3#