How do you solve #4y + 1= - 2y + 13#?

1 Answer
CW
Sep 14, 2016

#y=2#

Explanation:

1) Subtract 1 from both sides :

#=> 4y+1-1=-2y+13-1#
#=> 4y=-2y+12#

2) Addt 2y to both sides :
#=>4y+2y=-2y+2y+12#
#=>6y=12#

3) divide both side by 6
#=> (cancel6y)/cancel6=12/6#
#y=2# is the solution

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