How do you solve #4y+12=4#?

1 Answer
May 11, 2018

#y=-2#

Explanation:

You want to solve#4y+12=4#
We can think of this as some amount plus 12 = 4.
The amount itself, therefore, must be 12 less than 4, i.e. #4-12=-8#

We, therefore, have #4y=-8#.
But if 4 of something is -8, then that something must be 1/4 of -8 i.e. -2

It, therefore, follows that y=-2

In mathematical terms we have

#4y+12=4#
#4y+12-12=4-12=-8# (deduct 12 from both sides)
#4y=-8#
#(4y)/4=-8/4=-2# (divide both sides with 4)
#y=-2#