How do you solve #4y + 7- y > 3( y + 3)#?

1 Answer
Jan 16, 2018

See a solution process below:

Explanation:

First, group and combine like terms on the left side of the inequality:

#4y - y + 7 > 3(y + 3)#

#4y - 1y + 7 > 3(y + 3)#

#(4 - 1)y + 7 > 3(y + 3)#

#3y + 7 > 3(y + 3)#

Next, expand the term in parenthesis on the right side of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:

#3y + 7 > (3 * y) + (3 * 3)#

#3y + 7 > 3y + 9#

Now, subtract #color(red)(3y)# from each side of the inequality:

#3y - color(red)(3y) + 7 > 3y - color(red)(3y) + 9#

#0 + 7 > 0 + 9#

#7 > 9#

We know #7# is not greater than #9# therefore there are no values of #y# which make this inequality true.

Therefore, the solution is the null or empty set: #y = {O/}#