How do you solve #5= - 1+ | - 5x + 4|#?

1 Answer
Sep 19, 2017

See a solution process below:

Explanation:

First, add #color(red)(1)# to each side of the equation to isolate the absolute value function while keeping the equation balanced:

#color(red)(1) + 5 = color(red)(1) - 1 + abs(-5x + 4)#

#6 = 0 + abs(-5x + 4)#

#6 = abs(-5x + 4)#

The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent.

Solution 1:

#-6 = -5x + 4#

#-6 - color(red)(4) = -5x + 4 - color(red)(4)#

#-10 = -5x + 0#

#-10 = -5x#

#(-10)/color(red)(-5) = (-5x)/color(red)(-5)#

#2 = (color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5))#

#2 = x#

#x = 2#

Solution 2:

#6 = -5x + 4#

#6 - color(red)(4) = -5x + 4 - color(red)(4)#

#2 = -5x + 0#

#2 = -5x#

#2/color(red)(-5) = (-5x)/color(red)(-5)#

#-2/5 = (color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5))#

#-2/5 = x#

#x = -2/5#

The Solutions Are: #x = 2# and #x = -2/5#