How do you solve -5( 2c - 12) + 2= 20- 7c?

1 Answer
Sep 26, 2017

c=14

Explanation:

First, we look at the left side of the equation.

-5(2c-12)+2

We will look at -5(2c-12) for now and leave out +2.
We will distribute parentheses/brackets using: x(y+z)=xy+xz

Therefore, -5(2c-12) is the same as -5*2c cancel(+)-5(-12)

-5*2c-5(-12) is the same as -5*2c+5*12.

5*2c=10c and 5*12=60.

Therefore, the equation (with the +2) would be -10c+60+2.

60+2=62

->-10c+62

Now we put in the right side of the equation together with the left side.

-10c+62=20-7c

We subtract 62 from both sides:
-10c+62color(blue)-color(blue)62=20-7c color(blue)-color(blue)62

which is -10c=-7c-42

Add 7c to both sides:
-10c color(blue)+color(blue)7color(blue)c=-7c-42color(blue)+color(blue)7color(blue)c

Simplify: -3c=-42.

Divide both sides by 3

(-3c)/(-3)=(-42)/(-3)

Simplify:
c=14