How do you solve #-5(2x-6)=4(x+11)#?

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Answer 1 · 2017-03-13T06:17:13

#x# is equal to #-1#.

What I would first do, is expand.

#-5(2x-6)=4(x+11)#

#-10x+30=4x+44#

Then, I would combine like terms.

#-44+30=10x+4x#

#-14=14x#

Finally, isolate for #x#.

#-(14)/14=(14x)/14#

#-1=x#

We can double check by plugging in #-1# to the original equation.

#-5(2x-6)=4(x+11)#

#-5[2(-1)-6]=4[(-1)+11]#

#-5[-2-6]=4[10]#

#-5[-8]=4[10]#

#40=40#

We see that both sides of the equal sign are equal, thus, we can conclude that #x# is equal to #-1#.

Hope this helps :)