First, expand the terms on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:
#color(red)(-5)(-3x - 4) = -6x - 2#
#(color(red)(-5) xx -3x) + (color(red)(-5) xx -4) = -6x - 2#
#15x + 20 = -6x - 2#
Next, subtract #color(red)(20)# and add #color(blue)(6x)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#color(blue)(6x) + 15x + 20 - color(red)(20) = color(blue)(6x) - 6x - 2 - color(red)(20)#
#(color(blue)(6) + 15)x + 0 = 0 - 22#
#21x = -22#
Now, divide each side of the equation by #color(red)(21)# to solve for #x# while keeping the equation balanced:
#(21x)/color(red)(21) = -22/color(red)(21)#
#(color(red)(cancel(color(black)(21)))x)/cancel(color(red)(21)) = -22/21#
#x = -22/21#
