How do you solve $5 - 3 x = 7 (x - 1)$ $5-3x=7(x-1)$ ?

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Answer 1 · 2018-03-07T16:34:33

$x = 1.2$ $x=1.2$

$5 - 3 x = 7 (x - 1)$ $5-3x=7(x-1)$

Distribute and multiply the $7$ $7$ to $x$ $x$ and $- 1$ $-1$ so you get

$5 - 3 x = 7 x - 7$ $5-3x=7x-7$

Add $7$ $7$ to $- 7$ $-7$ and $5$ $5$ to get

$12 - 3 x = 7 x$ $12-3x=7x$

Add $3 x$ $3x$ to $- 3 x$ $-3x$ and $7 x$ $7x$ to get

$12 = 10 x$ $12=10x$

Divide $10$ $10$ on both sides to get

$1.2 = x$ $1.2=x$

How do you solve 5-3x=7(x-1)5−3x=7(x−1)5-3x=7(x-1)?