How do you solve #5/7=(x-2)/4#?

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Answer 1 · 2018-05-12T15:36:26

try to get rid of the fractions; Solve equation

multiply on both sides with your denominators (4 and 7)

#5/7 = (x-2)/4 # |*4

#(5*4)/7=(x-2)# |*7

#(5*4)=(x-2)*7#

#20=7x-14#

solve the equation by moving the x-parts to on side and the normal numbers to the other (always move by using the opposite compute-sign)

#20=7x-14# |+14

#20+14=7x#

#34=7x# |:7

#34/7=x#

#x=4 6/7#