# How do you solve #5/(8x)-1/2=7/(6x)# and check for extraneous solutions?

##### 1 Answer

Jul 7, 2017

#### Explanation:

#"multiply all terms by " 24x#

#rArr15-12x=28#

#rArr-12x=13rArrx=-13/12#

#color(blue)"As a check"#

#"left side "=5/(8xx-13/12)-1/2=-15/26-13/26=-14/13#

#"right side "=7/(6xx-13/12)=-14/13#

#rArrx=-13/12" is the solution"#