How do you solve #5/9=-2/3n#? Algebra Linear Equations One-Step Equations and Inverse Operations 1 Answer Acquaintance Jul 6, 2016 #-15/18 = n# Explanation: Given equation: #5/9 = -2/3 n# We need to divide out #-2/3#. To do this, we need to multiply by the reciprocal, which is #-3/2#. #(5times-3)/(9times2) = n# #-15/18 = n# Answer link Related questions What are One-Step Equations? How do you check solutions when solving one step equations? How do you solve one step equations involving addition and subtraction? How do inverse operations help solve equations? What are some examples of inverse operations? How do you solve for x in #x + 11 = 7#? How do you solve for x in #7x = 21#? How do you solve for x in # x - \frac{5}{6} = \frac{3}{8}#? How do you solve for f in #\frac{7f}{11} = \frac{7}{11}#? How do you solve for y in #\frac{3}{4} = - \frac{1}{2} \cdot y#? See all questions in One-Step Equations and Inverse Operations Impact of this question 1296 views around the world You can reuse this answer Creative Commons License