How do you solve #5+9x=2012#?

1 Answer
Feb 25, 2017

See the entire solution process below:

Explanation:

Step 1) Subtract #color(red)(5)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#5 + 9x - color(red)(5) = 2012 - color(red)(5)#

#5 - color(red)(5) + 9x = 2007#

#0 + 9x = 2007#

#9x = 2007#

Step 2) Divide each side of the equation by #color(red)(9)# to solve for #x# while keeping the equation balanced:

#(9x)/color(red)(9) = 2007/color(red)(9)#

#(color(red)(cancel(color(black)(9)))x)/cancel(color(red)(9)) = 223#

#x = 223#