First, subtract #color(red)(5)# from each segment of the system of inequalities to isolate the #n# term while keeping the system balanced:
#5 - color(red)(5) > n/6 + 5 - color(red)(5) > -1 - color(red)(5)#
#0 > n/6 + 0 > -6#
#0 > n/6 > -6#
Now, multiply each segment by #color(red)(6)# to solve for #n# while keeping the system balanced:
#color(red)(6) xx 0 > color(red)(6) xx n/6 > color(red)(6) xx -6#
#0 > cancel(color(red)(6)) xx n/color(red)(cancel(color(black)(6))) > -36#
#0 > n > -36#
Or
#n > -36# and #n < 0#
Or, in interval notation:
#(-36, 0)#