How do you solve $5 ln x = 35$ $5 ln x = 35$ and find any extraneous solutions?

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Answer 1 · 2016-05-30T16:42:44

$x = e^{7} = 1096.6$ $x=e^7=1096.6$ , nearly. There is no other solution.

There is 1 - 1 correspondence between the logarithmic and the

exponential inverse functions. They are single-valued.

How do you solve 5 ln x = 355lnx=355 ln x = 35 and find any extraneous solutions?