How do you solve 5+log(2x+1)=6?

Jul 16, 2016

$x = 4 \frac{1}{2}$

Explanation:

When working with equations which contain logs, each term must be a log term. We cannot work with a mixture of logs and numbers.

$5 + \log \left(2 x + 1\right) = 6$

$\log \left(2 x + 1\right) = 6 - 5$

$\log \left(2 x + 1\right) = 1$

$\log \left(2 x + 1\right) = \log 10 \text{ if" log A = log B, " then } A = B$

$2 x + 1 = 10$

$2 x = 9 \Rightarrow \text{ } x = 4 \frac{1}{2}$