How do you solve #5| x + 1| > 10#?

1 Answer
Mar 25, 2017

#x> -3 or x>1#

Explanation:

First, simplify the inequality as much as possible before you deal with the absolute value term:

#5|x+1| > 10#
# color(white)"x" |x+1| > 2 color(white)"XXX"# (dividing both sides by 5)

Therefore, #x+1# must either be greater than 2, or less than -2 for the equation to be true. So, we can split this equation into two equations and solve both of them to get our solution.

#color(white)"XXXXXXX" |x+1| > 2#

#x+1 > 2 color(white)"XXX" or color(white)"XXX" x+1 < -2#
#color(white)"X-X" x > 1 color(white)"XXX" or color(white)"XXXX-X" x < -3#

So our final solution is:

#x> -3 or x>1#

Or if the problem asks for interval notation:

#(-oo, -3) uu (1, oo)#

Final Answer