How do you solve $5 + x < 12$ $5+x<12$ ?

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Answer 1 · 2017-04-01T11:20:18

$x < 7$ $x\lt7$

originally $5 + x < 12$ $5+x\lt12$

"solving" means isolating for $x$ $x$ value...
$\cancel(5)+x\cancel(\color(red)(-5))\lt12\color(red)(-5)$
$x\lt7$

How do you solve 5+x<125+x<125+x<12?