How do you solve #-51= 5+ 8x#?

Question

517 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-28T02:18:23

See a solution process below:

Step 1) Subtract #color(red)(5)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(red)(5) - 51 = -color(red)(5) + 5 + 8x#

#-56 = 0 + 8x#

#-56 = 8x#

Step 2) Divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:

#-56/color(red)(8) = (8x)/color(red)(8)#

#-7 = (color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8))#

#-7 = x#

#x = -7#