Question

How do you solve `58= 3u + 16`?

Answer 1

`u=14`

Explanation:

The first step is to isolate the term with the variable, (`3u`)

Subtract `16` from both sides.

`58 -16= 3u +16-16`

`42 = 3u" "larr` now `divide 3`

`42/3 = (3u)/3`

`14 = u`