How do you solve #5c+3=15+4c-2#?

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Answer 1 · 2017-01-30T06:50:45

See the entire solution process below:

First, combine the constants on the right side of the equation:

#5c + 3 = 15 + 4c - 2#

#5c + 3 = 15 - 2 + 4c#

#5c + 3 = 13 + 4c#

Now subtract #color(blue)(3)# and #color(red)(4c)# from each side of the equation to isolate the #c# terms while keeping the equation balanced:

#5c + 3 - color(blue)(3) - color(red)(4c) = 13 + 4c - color(blue)(3) - color(red)(4c)#

#5c - color(red)(4c) + 3 - color(blue)(3) = 13 - color(blue)(3) + 4c - color(red)(4c)#

#(5 - 4)c + 0 = 10 + 0#

#1c = 10#

#c = 10#