How do you solve #5e - 10\leq 7e + 18#?

1 Answer
Jim G.
Oct 3, 2016

#e>=-14#

Explanation:

Collect terms with e to the left side of the inequation and numeric values to the right.

subtract 7e from both sides.

#5e-7e-10<=cancel(7e)cancel(-7e)+18#

#rArr-2e-10<=18#

now add 10 to both sides.

#-2ecancel(-10)cancel(+10)<=18+10#

#rArr-2e<=28#

To solve for e, divide both sides by - 2. However since this is an inequation whenever we divide/multiply by a negative quantity we must #color(blue)" reverse the direction of the inequality symbol"#

#(cancel(-2) e)/cancel(-2)>=28/(-2)#

#rArre>=-14" is the solution"#

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