How do you solve #-5k-19=5-13k#?

1 Answer
EZ as pi
May 8, 2016

You have to get all the variables on one side of the equation and all the numbers on the other.
The correct way to 'move' a term, is to add on its inverse to both sides.
The short cut is to put it on the other side and change the sign.

#-5k - 19 color(red)(+ 19) color(blue)(+ 13k) = 5 - 13k color(blue)( + 13k) color(red)(+ 19 ) #

The nett effect of this is:
#-5k cancel(- 19 color(red)(+ 19)) color(blue)(+ 13k) = 5 cancel(- 13k color(blue)( + 13k)) color(red)(+ 19 ) #

#-5k + 13k = 5 + 19#

# 8k = 24 " "# divide both sides by 3.

#k = 3#

The short method would look like this:
#-5k color(red)(- 19) = 5 color(blue)( - 13k) color(red)#

#-5k color(blue)( +13k) = 5 color(red)(+ 19)#

# 8k = 24 " "# divide both sides by 3.

#k = 3#

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