How do you solve #5r ( 14r + 9) = 0#?

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Answer 1 · 2017-02-24T23:50:24

See the entire solution process below:

To solve this equate each term on the left side of the equation to #0# and solve for #r#:

Solution 1)

#5r = 0#

#(5r)/color(red)(5) = 0/color(red)(5)#

#(color(red)(cancel(color(black)(5)))r)/cancel(color(red)(5)) = 0#

#r = 0#

Solution 2)

#14r + 9 = 0#

#14r + 9 - color(red)(9) = 0 - color(red)(9)#

#14r + 0 = -9#

#14r = -9#

#(14r)/color(red)(14) = -9/color(red)(14)#

#(color(red)(cancel(color(black)(14)))r)/cancel(color(red)(14)) = -9/14#

#r = -9/14#

The solution is: #r = 0# and #r = -9/14#